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[C/C++ 演算法]-用for迴圈 排成特殊”菱形” 剛才逛論壇發現這一題目，並且也有人回答，趕快發揮(C/P)的長才將它備份來，有需要的同好，歡迎來(C/P)一下^^。   #include int main (void) { int i, j, N; scanf ("%d", &N); for (i = 1; i <= N; i++) { for (j = 1; j <= N; j++) if (i <= N / 2) if (j <= (N+1)/2-i) putchar (' '); else if (j<=(N+1)/2) putchar ('*'); else if (j<=(N+1)/2+i-2) putchar (' '); else if (j==(N+1)/2+i-1) putchar ('*'); else break; else if (i == (N+1)/2) putchar ('*'); else if (j <= i-(N+1)/2) putchar (' '); else if (j == i-(N+1)/2+1) putchar ('*'); else if (j < (N+1)/2) putchar (' '); else if (j <= N-i+(N+1)/2) putchar ('*'); else break; putchar ('\n'); } return 0; } 來源出處：http://www.eyny.com/thread-8967525-1-3D41XTMV.html